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Mr. Math
United States
Приєднався 5 лип 2006
I share math and finance video lectures in my channel. I am particularly interested in publishing material for middle and high school students advanced in math. The AMC 10/12, AIME, ARML, Mandelbrot Comp., HMMT, Rice MT, USAMO, USAJMO are wonderful math competitions for advanced students seeking challenge and excitement.
Відео
2019 Poland Math Olympiad Geometry problem (Symmedian line, Incenter Excenter Lemma, Monge Theorem)
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2019 Polish Math Olympiad
2021 AIME I Problem 11 Geometry (with lots of circles)
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2021 AIME I Problem 11 Geometry (with lots of circles)
2021 Atlantic Hurricane Season Song (Educational)
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We can't wait for the upcoming hurricane season Atlantic hurricanes! en.wikipedia.org/wiki/2021_Atlantic_hurricane_season #Houston #Storms #Hurricances #Education #Broken_fence #Snow_Storm #Dead_plants
2021 AIME I Problem 15 -- Algebra of parabolas and circles
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TYPO: Typo at 16:41 when completing the square. Check pinned comment for correction. Luckily I was checking the rest of calculations from my notes and things are corrected two lines later.
2011 AMC 12A Problem 25
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One viewer commented I should solve this. Good luck to everyone watching this on the upcoming AMC 10/12 exams.
2020 AIME II Problem 14 (Unnecessarily long :D )
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I don't know why I keep doing that. I am too old for AIME problems!
2020 European Girls Math Olympiad (EGMO) Problem 6
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2020 European Girls Math Olympiad (EGMO) Problem 6
2020 European Girls MO (EGMO) Problem 3
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2020 European Girls MO (EGMO) Problem 3
2017 European Girls Math Olympiad (EGMO) Problem 1
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Geometry problem. Prove 4 points are concyclic. Solution uses simple angle chasing only.
2018 USAJMO Problem 1
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We use recursion to count. We show also how to solve a recursion.
2017 European Girls Math Olympiad Problem 5
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Typo at 17:40. 9 7 = 16 = 2^4 not 2^3. Luckily all we cared for was parity.
2017 European Girls Math Olympiad Problem 6
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2017 European Girls Math Olympiad Problem 6
2017 European Girls Math Olympiad - Problem 3
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2017 European Girls Math Olympiad - Problem 3
2019 Math Prize for Girls Problem 16
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2019 Math Prize for Girls Problem 16
2019 Math Prize for Girls Problem 19 "Three tricks"
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2019 Math Prize for Girls Problem 19 "Three tricks"
2019 European Girls Math Olympiad (EGMO) Problem 6
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2019 European Girls Math Olympiad (EGMO) Problem 6
2019 European Girls MO (EGMO) Problem #3
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2019 European Girls MO (EGMO) Problem #3
2019 USAMO Problem 5 (USAJMO Problem 6)
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2019 USAMO Problem 5 (USAJMO Problem 6)
2019 USAMO Problem 4 (JMO Problem 5)
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2019 USAMO Problem 4 (JMO Problem 5)
2019 USAMO Problem #2 (USAJMO Problem #3)
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2019 USAMO Problem #2 (USAJMO Problem #3)
2019 European Girls Math Olympiad (EGMO) Problem #4
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2019 European Girls Math Olympiad (EGMO) Problem #4
2019 European Girls Math Olympiad (EGMO) Problem #1
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2019 European Girls Math Olympiad (EGMO) Problem #1
2018 European Girls Math Olympiad (EGMO) Problem #1
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2018 European Girls Math Olympiad (EGMO) Problem #1
2018 European Girls Math Olympiad Problem #3
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2018 European Girls Math Olympiad Problem #3
2019 AIME II Problem 15 (Two solutions)
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2019 AIME II Problem 15 (Two solutions)
my bad. mis count.
why are there 26 syms.in the diag. but 24 in the calc.???
Great solution! thank you :)
why angle BI1A equal 90+theta/2?
i got totally stuck in a part
i wasnt stuck but i didnt wanted to take a+b common as i thought it will complicate question
Do you do olympiad classes sir
Do you do olympiad classes sir ?
1. Proof it is a surjective function And use this property and get f(0)=1 2.then put y=0 and you will get a relation between f(x-1)and f(x) And then simply find the sequence and It's done ❤️❤️❤️😫
One of the easiest p6
who is there after egmo? XD
It is good solution
what it will be if we coloringin to 6 colors,how many ways will be
In the calculation, simply replace 3's with 6's in the base of each exponent.
Thank you so much, this was a very nice explanation!
I am so wondering about a few things : 1. If we number them from 1 to n(n+1) Then we remove the n(n-1), then we make them closer all together, then we get the remaining players of order : a_1 < a_2 < ... < a_2n. Is it? 2. Does the main idea suggests that we need to prove that, out of n(n+1) we can obtain 2n players with height sequence is either increasing or decreasing?
Shouldn't the final result for c be y^2-b = 7^2-16 = 49-16 = 33 and not 49?
Amazing playlist sir. Really made me understand the incenter-excenter lemma well
angle PTR=TRA but PTR=TRA=SKR how?? someone please explain!!
There's a very simple method to solve this.
daily dose of dopamine :)
Searching for this explanation. Sera
Thanks. Your use of a concrete example of colouring of 2X2 chess board helped a lot. I am going to teach the derivation of finite crystallographic group of rotations in my course in crystallography. I will use this example.
Nice
clearly understand
How did you think that f(x) can be taken as alpha*n? Why not alpha*n + some constant say c?
Beautiful problem! Thanks. We never get tired of geometry aren't we ? 🙂
It looks like that KI pass through H in the drawing. Does it happen always or accidentally?
Not necessarily.
lovely!
I swear to god phantom points are one heck of a thing...
nice and neat
I did it in a different way
THIS IS SO BEAUTIFUL!!!!! Very nice solution!!!!!
Part (c) is actually easier than the video once you solve part (b). That is, since in part (b) you proved that f(m,n)≤½max(m,n), then you can make either m or n arbitrarily large and thus f(∞,n)<∞ which means that there is no constant upper bound C for which f(m,n)<C for all m,n
beautiful proof!!!
How do we prove that A, I and L are collinear
I feel like this was by far the hardest problem on the exam
نظرية جيدة . رسم واضح مرتب . شرح واضح مرتب . شكرا جزيلا لكم والله يحفظكم ويرعاكم ويحميكم جميعا . تحياتنا لكم من غزة فلسطين .
4:17
نظرية جميلة جيدة . رسم واضح مرتب . شرح واضح مرتب . شكرا جزيلا لكم والله يحفظكم ويرعاكم ويحميكم جميعا . تحياتنا لكم من غزة فلسطين .
Hi, I have worked on this problem on and off , for years. Thank you for this elegant solution, more elementary than the official solutions
The main issue I faced was I started by combining 1&2, and once we end up with a (summation) sigma on the LHS, it becomes hopeless
Where are you 😢 plz upload more
Very good explanation
Please make a full course on math olympiad basic to advance .
Thank you!
very good. Thanks for the big help.
7 yrs And Still Learning outcomes 🎉 thnx
Fantastic ❤❤❤❤❤
where do u think it would be by today's sstandards
It was in the first chapter of problem solving strageies and ot is a book done by almost everyone for national olympiad
Nice❤❤❤❤
5:00 uhh just look at the cyclic quad with two feet and point A on it and see that the opposite angle is 180-A?
For some reason nobody did a circle centered at M with radius MK. Radius zero is nit very intuitive so 😝
Oh I just realized he has two k’d in his diagram, i mean K as in the center of (AEF)